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The electric field outside a small, spherical, metallic charge q at distance r from the center of the charge is E=1/((4PiEpisolon)*(q/r^2)). The radius of the sphere is R. Use calculus to determine the potential at any r that is outside the sphere.
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We know that potential is related to Electric field as \[V=-\int_{\infty} ^{R=r} E.dR\] Can you try now?
@alwaysstruggling
So we would find that the final answer would be \[V = q/4 \pi \epsilon r\] Does that look right?
And thank you @ash2326
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