Cot x Sec^4 x = Cot x + 2tan x + tan^3 x
Is this an identity to be proven?
yes
Does your teacher care which side you work on?
They said to have me match the right side with the left, but I don't think it matters.
have you tried anything yet?
I was thinking I might be able to factor it.
to me, I replace sec^4 x = (1 = tan^2)^2 and then expand it, and then time cot , and get the RHS
1+tan^2 not 1=tan^2 sorry
thank you so much! that helps!
yw
i don't actually see how that works out. i get an extra 1 and the cotx is still multiplying by what is inside the factored out equation.
\[\cot x(1+\tan ^2x)^2=\cot x(1+2\tan ^2x+\tan ^4x)=\cot x \cot +2\cot x \tan ^2x+\cot x \tan ^4x\]
Hang on...I'll fix that
\[\cot x+2\cot x \tan ^2x+\cot x \tan ^4x\]
Do you agree so far?
Hoa...any mistakes there?
yes
So we have the cotx. Let's see if we can show that the other two terms are equal to the two terms on the right.
\[2\cot x \tan ^2x=2\cot x \tan x \tan x=2\tan x\]
Do you see that?
Now you do the same thing to the last term
And you will be done.
thank you! I will do that!
you're welcome and thanks to Hoa as well
thank you both!
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