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Chemistry 8 Online
OpenStudy (anonymous):

adf

OpenStudy (anonymous):

An nucleus that undergoes alpha decay emits a Helium nucleus. \[^{4} _{2} He\] 4 is the mass number (total neutrons and protons) 2 is the atomic number (total number of protons) So you would subtract a Helium nucleus from whatever is undergoing decay to find out what happens to the proton-neutron ratio.

OpenStudy (anonymous):

So I would take 2-4 and so the answer would be B @dimensionx

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