Question

log7^n=(2/3)log7^8

Answer 1

log base 10?

Answer 2

How do you solve it? I'm not sure where to start.

Answer 3

first begging by writen it clear it is \[\log_{10}7^{n} = (2/3)\log_{10}7^{8} ???? \]

Answer 4

Where does the 10 come from?

Answer 5

the logarithmic functions has a base usually when u write log it meants that it has base 10

Answer 6

the base on this one is 7.

Answer 7

it is n a exponent?

Answer 8

yes, n is the exponent for the left side of the equation

Answer 9

and the base of the exponent?

Answer 10

n is the exponent; and its base?

Answer 11

the base is 7

Answer 12

so the base of the log function is 10

Answer 13

and 7 is the base of n

Answer 14

$$
log_7(n)=\cfrac{2}{3}log_7(8) ?
$$

Answer 15

it would be great if the student write the eqation like jdoe001 or like me

Answer 16

how jdoe0001 wrote the equation is the correct way

Answer 17

well i dont understand jdoe011 help us

Answer 18

ohhh i get it

Answer 19

well so u must remember some property about the logarithms the first one is this