y^2-49/(y-7)(y-7) / 5y+35/y^2-7y
supposed to be a division sign not an X!
\[\frac{(y^2-49)}{(y-7)(y-7)} \div \frac{(5y+35)}{(y^2-7y)}\]
Ok! So for rational divition, you are merely multiplying by the reciprocal. Think of it like this, \[\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}\]
I'd do some factoring as the 1st step and when you divide by a fraction the rule is flip and multiply... or find the reciprocal and multiply so you get \[\frac{(y - 7)(y + 7)}{(y - 7)(y - 7)} \times \frac{y( y - 7)}{5(y + 7)}\] all you need to do is cancel common factors.
So, you would then go about this problem much like the last one that we worked on.
thank you both!! so then is it just y/5 ?
Yes, it should be.
you're a saint, thanks!!
No problem, you have any more questions?
haha well I have 9 questions like this left to answer so i'm sure i will be needing help! i'll post more as I keep going! :)
Ok, if you need help just type @austinL in a response.
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