Question

x^2-3x-10/2x^2-11x+5 / x^2-5x+6/2x^2-7x+3

Answer 1

@austinL

Answer 2

\[\frac{\frac{(x^2-3x+10)}{(2x^2-11x+5)}}{\frac{(x^2-5x+6)}{(2x^2-7x+3)}}\]

Answer 3

Ok, you are dividing a fraction by a fraction, so what did I tell you that you should do in that case?

Answer 4

I may have typed that wrong. it looks like this.

Answer 5

but anyways, reciprocal

Answer 6

Exactly, you multiply the numerator by the reciprocal of the denominator.
\[\frac{(x^2-3x-10)}{(2x^2-11x+5)} \times \frac{(2x^2-7x+3)}{(x^2-5x+6)}\]

Answer 7

I don't know how to factor it

Answer 8

Ok, gimme a sec.

Answer 9

Lets start with the numerator of the first half.
\[x^3-3x-10\]

Answer 10

(x+5)(x-2)

Answer 11

it's the 2x ones i don't get

Answer 12

FOIL that back out and see what you get? I don't believe that is correct.

Answer 13

(x-5)(x+2)

Answer 14

Correct! Now, lets try one of those 2x ones.

Answer 15

What multiplied together is 2x^2?

Answer 16

2x times x?

Answer 17

right so you would have this correct?
\[(x-?)(2x-?)\]

Answer 18

yeah

Answer 19

So, what times 2, plus what would give you 11?

Answer 20

5 times 2 plus one?

Answer 21

Correct, so where would the 5 go, and where would the 1 go?

Answer 22

so (x+5)(2x+1)

Answer 23

Correct, except they are negative because it is
\[2x^2-11x+5\]

Answer 24

(x-5)(2x-1)

Answer 25

so would the other one be (x-3)(2x-1) ?

Answer 26

Yes!

Answer 27

So what does that give us now? With it all factored out.

Answer 28

so like this?

Answer 29

Correct!

Answer 30

\[\frac{(x+2)}{(x-2)}\]

Answer 31

thanks so much! the first one was hard to read this is what it said

Answer 32

No problem. I was able to read it, it was just a little fuzzy and dark. You have another problem?

Answer 33

I am having trouble with this one as well