Question

x2+9x+4=0

Answer 1

Use quadratic formula

Answer 2

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] when you have \(ax^2+bx+c\)

Answer 3

Simplifying
x2 + -9x + 20 = 0

Reorder the terms:
20 + -9x + x2 = 0

Solving
20 + -9x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + -1x)(5 + -1x) = 0

Subproblem 1
Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying
4 + -1x = 0

Solving
4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x = 0 + -4
-1x = 0 + -4

Combine like terms: 0 + -4 = -4
-1x = -4

Divide each side by '-1'.
x = 4

Simplifying
x = 4
Subproblem 2
Set the factor '(5 + -1x)' equal to zero and attempt to solve:

Simplifying
5 + -1x = 0

Solving
5 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1x = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1x = 0 + -5
-1x = 0 + -5

Combine like terms: 0 + -5 = -5
-1x = -5

Divide each side by '-1'.
x = 5

Simplifying
x = 5
Solution
x = {4, 5}

Answer 4

\[x^2+9x+4=0\]
\[x={-b\pm\sqrt{b^2-4ac}\over2a}\]where \(ax^2+bx+c=0\)

Answer 5

Wrong problem @nathan917

Answer 6

thank you!!!!!

Answer 7

Quadratic formula:

x = (-9 +- sqrt(45))/2

= (-9 +- 3*sqrt(5))/2

= 3(-3 +- sqrt(5))/2

How about this?