Find the vector equation for the line through the point P = (1; 3;
can you find the line of solutions that is the intersection of the planes?
@cmtejeda knock, knock, do you still need help?
Please. So does this mean that I need to cross both normal vectors from the two planes to find the line of intersections? And then add that vector to the given point?
yes, let n_1 is normal vector of plan 1 and n_2 is normal vector of plan2 Cross them to get the direction vector of the intersection line
thanks!!
ok, do the stuff.
Cross-products, you need help, @cmtejeda ?
@satellite73,I believe i got it, thanks. But i have a question about another problem:Find the shortest distance between the lines parametrized by (1 + s; 2; 3 - s) and (0; 1 + 2t; 3 + t). I see that the the lines are perpendicular, so if i cross both normal vectors will that give me the shortest distance?
@cmtejeda how can it be? someone helps you and you call another one to say something like that? unbelievable!!!!
At my request, @Hoa I was incapable of answering the next question.
Thanks, sorry it looked wrong on my part.
@cmtejeda do you work with line integral in vector field? I'm struggling with that stuff now. watching the videos but still not get how they got that parametric equation to plug back to the equation.
Sorry, im struggling with most vector involved problems too. i fail to understand the full concept of them.
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