Add: 4/x^2-10x+24 + x+1/x-4
\[\frac{ 4 }{ x ^{2}-10x+24 } + \frac{ x+1 }{ x-4 }\]
lets factor out the \[x^2-10x+24\]
So x(x-12)(x+2) ?
Oh wait that would make -24 @_@.
:)
Or is that right?
nope. thats wrong two numbers that multiply to +24 and add up to -10
-6 & -4
bingo so, the factors are: \[(x-6)(x-4)\]
x(x-6)(x-4) right?
now, lets write the give expression again \[ {4\over(x-6)(x-4)}+{x+1\over x-4} \]
there are only two terms no neeed for the extra "x"
now, just like the regular fractions, we make the denominator common
\[ {4\over(x-6)(x-4)}+{x+1\over x-4}\times{x-6\over x-6} \]
\[ =\frac{4+(x+1)(x-6)}{(x-6)(x-4)}\\ =\frac{4+x^2-6x+x-6}{(x-6)(x-4)}\qquad\text{I expanded the product}\\ =\frac{x^2-5x-2}{(x-6)(x-4)} \] The numerator cannot be simplified easily. so, we can leave our answer here
Thanks so much! :)
yw
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