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Mathematics 20 Online
OpenStudy (anonymous):

(Algebra) Find the sum of x+a; if {x;a} c Q+

OpenStudy (anonymous):

\[x^{x}=(2^{x})^{-1}\] and \[a^{2}=27^{a-1}\]

OpenStudy (anonymous):

i think if \(x^x=2^{-x}\) then \(x=\frac{1}{2}\)

OpenStudy (anonymous):

great now I can not find a.

OpenStudy (anonymous):

that because \(2^{-x}=(\frac{1}{2})^x\)

OpenStudy (anonymous):

yeah that kind of sucks maybe we can guess

OpenStudy (anonymous):

i guess 1

OpenStudy (anonymous):

it is a good guess, because it obviously works unfortunately, it is not the only correct answer

OpenStudy (anonymous):

I've got the answer but I do not know how to find a. I mean the process.

OpenStudy (anonymous):

try a= 1/3 I need to know how T_T

OpenStudy (anonymous):

as we say in the math biz, find \(a\) "by inspection"

OpenStudy (anonymous):

you cannot solve this with algebra, so forget that you can perhaps solve by graphing both and see where they intersect

OpenStudy (anonymous):

but in the exam is not allowed to use calculator or a computer

OpenStudy (anonymous):

ok then you just have to guess

OpenStudy (anonymous):

apparently there are three answers

OpenStudy (anonymous):

i am guessing you are looking for some step by step algorithm for solving this, but i am fairly certain there is not one you have to guess and check

OpenStudy (anonymous):

you've got a point

OpenStudy (anonymous):

there is a negative answer also, but i don't know what it is, probably not rational

OpenStudy (anonymous):

in my book there's only one. I'd like to have a algebra teacher to help me out. Do you have a teacher? Can you ask them?

OpenStudy (anonymous):

try it in wolfram, when you get the answer, go to "approximate form' you will see that the negative answer is probably not a repeating decimal

OpenStudy (anonymous):

Please Forgive me English is not my first language

OpenStudy (anonymous):

clearly there is more than one answer there are three, although if the negative answer in not rational you can ignore that one

OpenStudy (anonymous):

your english seems pretty good to me

OpenStudy (anonymous):

maybe the book just ignored the obvious answer of 1 and used only \(\frac{1}{3}\)

OpenStudy (anonymous):

ok thanks. I'm trying to solve another one. Would you like to see it?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

\[(\sqrt{\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}}}+ \sqrt[4]{6})^{4}\] and the answer in the book and calculator is 96.

OpenStudy (anonymous):

but we do not use calculator in the classroom, I do, but at home

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