(Algebra) Find the sum of x+a; if {x;a} c Q+
\[x^{x}=(2^{x})^{-1}\] and \[a^{2}=27^{a-1}\]
i think if \(x^x=2^{-x}\) then \(x=\frac{1}{2}\)
great now I can not find a.
that because \(2^{-x}=(\frac{1}{2})^x\)
yeah that kind of sucks maybe we can guess
i guess 1
it is a good guess, because it obviously works unfortunately, it is not the only correct answer
I've got the answer but I do not know how to find a. I mean the process.
try a= 1/3 I need to know how T_T
as we say in the math biz, find \(a\) "by inspection"
you cannot solve this with algebra, so forget that you can perhaps solve by graphing both and see where they intersect
but in the exam is not allowed to use calculator or a computer
ok then you just have to guess
apparently there are three answers
i am guessing you are looking for some step by step algorithm for solving this, but i am fairly certain there is not one you have to guess and check
you've got a point
there is a negative answer also, but i don't know what it is, probably not rational
in my book there's only one. I'd like to have a algebra teacher to help me out. Do you have a teacher? Can you ask them?
try it in wolfram, when you get the answer, go to "approximate form' you will see that the negative answer is probably not a repeating decimal
Please Forgive me English is not my first language
clearly there is more than one answer there are three, although if the negative answer in not rational you can ignore that one
your english seems pretty good to me
maybe the book just ignored the obvious answer of 1 and used only \(\frac{1}{3}\)
ok thanks. I'm trying to solve another one. Would you like to see it?
sure
\[(\sqrt{\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}}}+ \sqrt[4]{6})^{4}\] and the answer in the book and calculator is 96.
but we do not use calculator in the classroom, I do, but at home
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