Find the rate of change of the area of a circle per second with respect to its radius r when r = 5 cm.
@agent0smith @Noemi95 @Shannon20150 @91004775
take the formula for the area of a circle you are trying to find dA/dr
\[A=\pi r^2\]\[\frac{ dA }{ dt }=2 \pi r \frac{ dr }{ dt }\]
Evaluate the derivative at r = 5. To find the the dA/dt however, we also need dr/dt, the rate at which the radius is changing.
Did they give a dr/dt...?
with respect to radius, not with respect to time
ok then
@Peter14 "Find the rate of change of the area of a circle per second with respect to its radius" The wording is kinda confusing, really...
Unless we just have to leave it in terms of dr/dt.
OOps lol. Sorry I thought it was with respect to time. So it actually becomes:\[\frac{ dA }{ dr }=2 \pi r\] So at r = 5, it becomes:\[\frac{ dA }{ dr }=10 \pi\]
And you need to include the units.
@genius12 that's what I meant about the misleading wording: "Find the rate of change of the area of a circle per second with respect to its radius"
Thanks Sir
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