Question

My textbook says that the anti-derivative of f(x)=x^2+x-2 is G(x)=1/3x^3 + 1/2x^2 -2x
...??????...... I though the anti-derivative would be G(x)=1/3x^3 + 1/2x^2 -2....... where did the (...2x) come from ????

Answer 1

2x^0+1 =2x remember add 1 to the power of x and in this case the power of x is 0

Answer 2

Yea i knw but the f(x) part of the equation jus has a plain minus 2 at the end of it... I understand the add 1 to the power of x concept but the last term in the f(x) equation did not have an x on the end of it
I just dont understand where the x came from in the antideriv part ( the last term in the antideriv)

Answer 3

oooooo wait . is it cuz it never existed for the last term of f(x) that we tack on x^0+1 to the last term of f(x) (2)

Answer 4

because 2(x)^0 and anything to the power of is one.
ant der of 2 is 2x because der of 2x is 2

Answer 5

got it?

Answer 6

Ahh . yes thank u

Answer 7

now can u do this
what is anti deri of x^5+3x+9

Answer 8

x^6/6 + 3x^2/2 +9x

Answer 9

correct?

Answer 10

well done....

Answer 11

:) thank u

Answer 12

anytime