Question

The volume of a cube is increasing at the rate of 8 cm
3
/s. How fast is the
surface area increasing when the length of an edge is 12 cm?

Answer 1

@terenzreignz

Answer 2

Same as here
http://openstudy.com/study#/updates/517df4ebe4b0be6b54ab65e2
except
\[\huge \frac{dV}{dt}=9\]

and
x = 12

Answer 3

\huge \frac{dS}{dt}=\frac{dS}{dV}\cdot\frac{dV}{dt}=\frac{\frac{dS}{dx}\times \frac{dV}{dt}}{\frac{dV}{dx}}

Answer 4

Sorry...
\[\huge \frac{dS}{dt}=\frac{dS}{dV}\cdot\frac{dV}{dt}=\frac{\frac{dS}{dx}\times \frac{dV}{dt}}{\frac{dV}{dx}}\]

Answer 5

Thank you SIr