Question

medal awarded for answer equation will be in comments

Answer 1

[(2-3 \sqrt-6) _-4+\sqrt-6\]
a)\[10+4i \sqrt6\]
b) \[12-16i \sqrt6\]
c)\[-8+12i \sqrt6\]\
d)\[-4+7i \sqrt6\]

Answer 2

4x + 6y = 14
-2x + 2y = -2

Answer 3

wha tnow

Answer 4

Is this your question\[(2-3 \sqrt{-6})-4+\sqrt{-6}\]?

Answer 5

yes it is my question @ callisto

Answer 6

Consider \(\sqrt{-6}\),
\[\sqrt{-6}=\sqrt{-1 \times 6} = \sqrt{-1}\times\sqrt{6}=6i\]
Got this part?

Answer 7

ok so i replace sqrt of -6 with 56i and then just do the work?

Answer 8

sqrt of -6 with \(\sqrt{6}i\)

Answer 9

6i

Answer 10

okay so then what do i do

Answer 11

Hmm... why is it 6i but not \(\sqrt{6}i\)?

Answer 12

i meant sqrt 6i
how do you go about the equation with sqrt

Answer 13

Your question is not an equation, just an expression. Your task is to simply the expression given.

Answer 14

yes so i really have no idea how to do this

Answer 15

I made a typo above, it should be
\[\sqrt{-6}=\sqrt{-1 \times 6} = \sqrt{-1}\times\sqrt{6}=\sqrt{6}i\]Sorry again :(

Answer 16

its okay

Answer 17

As mentioned above, replace \(\sqrt{-6}\) with \(\sqrt{6}i\)
\[(2-3 \sqrt{-6})-4+\sqrt{-6}\]\[=(2-3 \sqrt{6}i)-4+\sqrt{6}i\]Then, add/subtract the "like terms"

Answer 18

that is to do addition for the real part and imaginary part (those terms with i) respectively.

Answer 19

okay so i end up with what? becaus ethe answer i get ais wrong says the teacher

Answer 20

What have you got?

Answer 21

For some reasons, I think the question you typed there was wrong.

Answer 22

12-16i sqrt6

Answer 23

Can you please check the question again?

Answer 24

yesy equation is typed corrctly

Answer 25

i gpt it right now thanks for your help

Answer 26

You're welcome...