Question

What is the solution of the linear-quadratic system of equations?

Answer 1

HELP!

Answer 2

@mathstudent55 help!

Answer 3

@nubeer @phi

Answer 4

use substitution method to solve this.

Answer 5

substitute y = x+2

Answer 6

im confused :P

Answer 7

actually, u can just substitte the first equation into the second one much more easier.
you see how it says y = ____ for the first one. just take that whole polynomial and put it on the second in place of "y". and solve.

Answer 8

oh. okay! hold on lemme try!

Answer 9

so like: x^2+5x-3=x^2+5-3-x=2?

Answer 10

@ganeshie8

Answer 11

y = x^2+5x-3 -------(1)
y-x = 2 ------------(2)

Answer 12

from (2),

y = x+2

substitute this value in (1) for y

=>

x+2 = x^2 + 5x -3

x^2 + 4x -5 = 0

solve this equation for x values

Answer 13

okay :)

Answer 14

x^2 + 4x -5 = 0

x^2 +5x - x -5 = 0

x(x + 5) -1(x+5) = 0

(x+5)(x-1) = 0

x = -5 or 1

Answer 15

thank you so much :)

Answer 16

substitute these two x values in (2), to get y values

x = -5 => y = ?

x = 1 => y = ?

can u find y ha..

Answer 17

i think so :P lol

Answer 18

good, then :)

Answer 19

after finding y values, u need to show solutions as ordered pairs like this : - (x1, y1) , (x2, y2)

Answer 20

-3?? lol

Answer 21

thats one y value, find second also

Answer 22

and y=3

Answer 23

perfect ! so the solution set is ?

Answer 24

can you help with this one? Simplify the number using the imaginary unit i.

Answer 25

square root -16

Answer 26

(-5,-3) , (1,3)