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Mathematics 7 Online
OpenStudy (anonymous):

Model each rule with a table of values and a graph 12. f(x)=1.5x-3 13. f(x)=\[-x^{2}+4\]

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

@luckythebest

OpenStudy (anonymous):

@nubeer

jimthompson5910 (jim_thompson5910):

to get a table, you just plug in various values of x to get corresponding values of y

jimthompson5910 (jim_thompson5910):

so when x = 0 you plug it into f(x) = 1.5x - 3 to get f(x) = -3 so x = 0 and y = -3

jimthompson5910 (jim_thompson5910):

one row in your table for #12 is 0 -3

OpenStudy (anonymous):

okay then what do we do to get more on the table

jimthompson5910 (jim_thompson5910):

plug in x = 1 to get f(x) = ???

OpenStudy (anonymous):

x=1 y=-1.5

jimthompson5910 (jim_thompson5910):

good, you keep doing that until you have a table big enough

OpenStudy (anonymous):

and do i do 13 like that too ?

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

once you get your table, you can use it to graph

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

ok post what you got again

OpenStudy (anonymous):

f(x)=4??

jimthompson5910 (jim_thompson5910):

how did you get 4

OpenStudy (anonymous):

i put 0 for x ???

jimthompson5910 (jim_thompson5910):

ok great, you should say when x = 0, f(x) = 4

jimthompson5910 (jim_thompson5910):

so one row in your table for #13 is 0 4

OpenStudy (anonymous):

okay then do it how we did the other one right

jimthompson5910 (jim_thompson5910):

yes plug in other various values of x to get corresponding values for y

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