Mathematics
7 Online
OpenStudy (anonymous):
Model each rule with a table of values and a graph
12. f(x)=1.5x-3
13. f(x)=\[-x^{2}+4\]
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
@luckythebest
OpenStudy (anonymous):
@nubeer
jimthompson5910 (jim_thompson5910):
to get a table, you just plug in various values of x to get corresponding values of y
jimthompson5910 (jim_thompson5910):
so when x = 0
you plug it into f(x) = 1.5x - 3 to get f(x) = -3
so x = 0 and y = -3
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jimthompson5910 (jim_thompson5910):
one row in your table for #12 is
0 -3
OpenStudy (anonymous):
okay then what do we do to get more on the table
jimthompson5910 (jim_thompson5910):
plug in x = 1 to get f(x) = ???
OpenStudy (anonymous):
x=1 y=-1.5
jimthompson5910 (jim_thompson5910):
good, you keep doing that until you have a table big enough
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OpenStudy (anonymous):
and do i do 13 like that too ?
jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
once you get your table, you can use it to graph
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
ok post what you got again
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OpenStudy (anonymous):
f(x)=4??
jimthompson5910 (jim_thompson5910):
how did you get 4
OpenStudy (anonymous):
i put 0 for x ???
jimthompson5910 (jim_thompson5910):
ok great, you should say
when x = 0, f(x) = 4
jimthompson5910 (jim_thompson5910):
so one row in your table for #13 is
0 4
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OpenStudy (anonymous):
okay then do it how we did the other one right
jimthompson5910 (jim_thompson5910):
yes plug in other various values of x to get corresponding values for y