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An object with a massof 100 grams (0.100 kg) is dropped from a certain height and has a velocity of 60 meters/second. If the potential energy of this object is 179.99 joules, how high was the object when it was dropped? a) 9.2 x 10^1 meters. b) 1.8 x 10^2 meters. c) 9.8 x 10^2 meters. d) 1.0 x 10^2 meters.
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So when the speed is 60m/s the potential energy was transformed into kinetic energy. This means:\[\frac{ 1 }{ 2 }mv ^{2}=mgh=PE=KE\]If you solve for h you get this which then you need to evaluate to get the answer:\[h=\frac{ v ^{2} }{ 2g }\]
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