A Wheel of Fortune-ish wheel is spun 90 times and the results are indicated in the table below. Each outcome on the wheel is supposed to be equally likely. Is the sample enough evidence to suggest that each outcome is not equally likely?

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anonymous · Answer

attachment

anonymous · Answer

@.Sam. @amistre64 @hartnn @Hero @Luis_Rivera @Mertsj @mukushla @reemii @zepdrix  anyone?

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@Luis_Rivera

anonymous · Answer

@schmidtdancer did you ever find the answer to this? Im stuck on this as well :(

anonymous · Answer

For anyone who still needs this:
H0: The outcomes are equally likely
Ha: The outcomes are not equally likely

We are going to use the x^2 GOF- Test on the calculator
first we need to put the data into lists
L1 will be our observed outcomes
L2 will be our expected outcomes
To find the expected value: 90/6=15
STAT Edit: 
L1: 16, 14 ,23, 12, 14, 11
L2: 15, 15, 15, 15, 15, 15

STAT, TESTS, x^2 GOF-Test (D)
observed: L1
expected: L2
df: 6-1= 5

calculate that and it will give you the results
You should get: x^2= 6.133
p-value= .29

Since .29>.05, at a 5% significance level, there is not sufficient evidence that the outcomes are not equally likely. We fail to reject the null hypothesis.