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OpenStudy (anonymous):
what is the molality of a water solution that has a boiling point of 102.00 degrees celcious? water has a boiling point of 0.52 degrees celcious/m.
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OpenStudy (anonymous):
\[\Delta Tb = 102 - 100 = 2\] \[\Delta Tb = m \times Kb\] 2 = m x 0.52 m = 2/0.52 = 3.84 molal
OpenStudy (anonymous):
thaaank youuu
OpenStudy (anonymous):
ur welcome
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