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OpenStudy (anonymous):

BatCo, a company that sells batteries, claims that 67.5% of their batteries are in working order. How many batteries would you expect to buy, on average, to find one that does not work. Help!

OpenStudy (anonymous):

okay that was wrong sorry if \(67.5\%\) work, then \(32.5\%\) do not i.e. the probability that one does not work is \(0.325\) the expected number to buy therefore is the reciprocal of \(0.325\) whatever that is

OpenStudy (anonymous):

This question seem to be missing some data, cause even though the percentage of batteries that won't work is known, there isn't any actual number of batteries I can use the percentage on. Sigh.. Maybe I should write the reviews.

OpenStudy (anonymous):

no it is not missing information the expected waiting time is the reciprocal of the probability

OpenStudy (anonymous):

if one out of every 100 batteries are defective, then you expect to have to test 100 before you find a defective one

OpenStudy (anonymous):

if the probability that a battery is defective is \(0.325\) then you expect to have to test \[\frac{1}{.325}=3.0769...\] before you get a defective one

OpenStudy (anonymous):

assuming independence, which you are in this case

OpenStudy (anonymous):

thank you, for the help. Now I understand xD

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