BatCo, a company that sells batteries, claims that 67.5% of their batteries are in working order. How many batteries would you expect to buy, on average, to find one that does not work. Help!
okay that was wrong sorry if \(67.5\%\) work, then \(32.5\%\) do not i.e. the probability that one does not work is \(0.325\) the expected number to buy therefore is the reciprocal of \(0.325\) whatever that is
This question seem to be missing some data, cause even though the percentage of batteries that won't work is known, there isn't any actual number of batteries I can use the percentage on. Sigh.. Maybe I should write the reviews.
no it is not missing information the expected waiting time is the reciprocal of the probability
if one out of every 100 batteries are defective, then you expect to have to test 100 before you find a defective one
if the probability that a battery is defective is \(0.325\) then you expect to have to test \[\frac{1}{.325}=3.0769...\] before you get a defective one
assuming independence, which you are in this case
thank you, for the help. Now I understand xD
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