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OpenStudy (anonymous):
what is the freezing point of a solution that contains 1.25 moles of solute in 0.750kg water??? water has a freezing point depression of -1.86 degrees celcious/m
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OpenStudy (anonymous):
molal = 1.25 x (1000/750) = 1.67 delta Tf = 1.67 x (-1.86) = -3.11 degree celcius
OpenStudy (anonymous):
thaaanks
OpenStudy (anonymous):
ur welcome
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