What is the number of solutions and solution of 3x+2y=10 and 3x+2y=2 ??
@Mertsj help please?
they are identical on the left side, but different on the right what does that tell you?
let us rewrite the equations in slope-intercept form. what do we get as slopes for the two lines?
@electrokid the slope is 2
\(y = mx+b\) re-arrange the equations like this.
2y=3x+10 and 2y=3x+2
yes. then divide by "2"
because we want "y" on its own
let me show the first one \[3x+2y=10\\ -3x\quad-3x\\ ------\\ 2y=-3x+10\\\text{divide by 2}\\ {2y\over 2}={-3\over 2}x+{10\over 2}\\ \boxed{y={-3\over2}x+5} \]similarly, for the second one
i got y=3/2+5 and y=3/2+1
you missed the "x" in them
oh yeah my bad but i do know what you mean, and my next step would be what?
what did you get for the second equation?
and what do we get for the slopes of each line?
well?
i will butt in for a second, and then butt out how is it possible for \(3x+2y\) to equal two different numbers? it is not
the slope is 3/2 for both
-3/2 for both and lines with equal slopes are parallel to each other. since parallel lines never intersect, there are NO SOLUTIONS for the given equations
kapeesh?
kapeesh xD and my hw also asks for the solution though?
ok i will but back in if \(3x+2y=10\) then it cannot also equal 2, and vice versa
so, what will your answer be for that? @satellite73 that is logical. Teachers usually want the answer using the "textual" method :/
idk i got 0
@electrokid ^
0 what? 0 number of solutions there are no solutions.. i.e., there is no such pair of (x,y) that will lie on both the lines since they are parallel |dw:1367285559443:dw|
so then why would my teacher put solutiion in my hw if there isnt any?
to trick ya
so im just suppose to put 0,0 on there @electrokid
(0,0) is a point. so you cannot put that. what is the number of solutions? __ what are the solutions? __ explain
the solutions are 5 and 1
@electrokid is it right?
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