Chemistry
6 Online
OpenStudy (anonymous):
PLEASE HELP. Multiple choice.
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OpenStudy (anonymous):
OpenStudy (chmvijay):
all the above :) u try
OpenStudy (anonymous):
all because they have same number of mol
No of particles = moles x Avogadro no
OpenStudy (anonymous):
Thanks guys!
OpenStudy (chmvijay):
its no of molecules or atoms(particle is not correct term but htey have used it no problem ) =moles * Avogadro no
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OpenStudy (anonymous):
ur welcome
OpenStudy (chmvijay):
ur welcome LOL:)
OpenStudy (anonymous):
Can you guys help me on another?
OpenStudy (chmvijay):
double dispalcement
OpenStudy (anonymous):
what about these two?
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OpenStudy (anonymous):
combustiobn
OpenStudy (chmvijay):
yaa its combustion
OpenStudy (chmvijay):
both are combustion
OpenStudy (chmvijay):
enough now LOL i have some work @awanyulian will help you out for ur other problems
OpenStudy (anonymous):
Wait one more! ahha can you check my answer on this question?
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OpenStudy (chmvijay):
ur right LOL
OpenStudy (anonymous):
THANKS! :DDDD
OpenStudy (anonymous):
the last one must be combustion
OpenStudy (anonymous):
Oh yeah sorry I messed up. What about this one?
OpenStudy (chmvijay):
yaa last one must be combustion mean A option LOL
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OpenStudy (chmvijay):
LOL bye i have seriously some work @awanyulian will help you out
OpenStudy (anonymous):
okay :(
OpenStudy (chmvijay):
:)
OpenStudy (anonymous):
@awanyulian help?
OpenStudy (anonymous):
First reaction the answer is last optin
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OpenStudy (anonymous):
2nd reaction the answer is second option
OpenStudy (anonymous):
Thank you, is my answer right?
OpenStudy (anonymous):
Also what about this one? Am I right?
OpenStudy (anonymous):
@awanyulian
OpenStudy (chmvijay):
ur right LOL