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Chemistry 6 Online
OpenStudy (anonymous):

PLEASE HELP. Multiple choice.

OpenStudy (anonymous):

OpenStudy (chmvijay):

all the above :) u try

OpenStudy (anonymous):

all because they have same number of mol No of particles = moles x Avogadro no

OpenStudy (anonymous):

Thanks guys!

OpenStudy (chmvijay):

its no of molecules or atoms(particle is not correct term but htey have used it no problem ) =moles * Avogadro no

OpenStudy (anonymous):

ur welcome

OpenStudy (chmvijay):

ur welcome LOL:)

OpenStudy (anonymous):

Can you guys help me on another?

OpenStudy (chmvijay):

double dispalcement

OpenStudy (anonymous):

what about these two?

OpenStudy (anonymous):

combustiobn

OpenStudy (chmvijay):

yaa its combustion

OpenStudy (chmvijay):

both are combustion

OpenStudy (chmvijay):

enough now LOL i have some work @awanyulian will help you out for ur other problems

OpenStudy (anonymous):

Wait one more! ahha can you check my answer on this question?

OpenStudy (chmvijay):

ur right LOL

OpenStudy (anonymous):

THANKS! :DDDD

OpenStudy (anonymous):

the last one must be combustion

OpenStudy (anonymous):

Oh yeah sorry I messed up. What about this one?

OpenStudy (chmvijay):

yaa last one must be combustion mean A option LOL

OpenStudy (chmvijay):

LOL bye i have seriously some work @awanyulian will help you out

OpenStudy (anonymous):

okay :(

OpenStudy (chmvijay):

:)

OpenStudy (anonymous):

@awanyulian help?

OpenStudy (anonymous):

First reaction the answer is last optin

OpenStudy (anonymous):

2nd reaction the answer is second option

OpenStudy (anonymous):

Thank you, is my answer right?

OpenStudy (anonymous):

Also what about this one? Am I right?

OpenStudy (anonymous):

@awanyulian

OpenStudy (chmvijay):

ur right LOL

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