How many different arrangements of the letters in the word PARALLEL are there?
if all the letters were different it would be \(8!\)
56 3,360 40,320
but since you have 2 "A" that you cannot tell apart, and also three identical "L" it is \[\frac{8!}{2!3!}\]
do you know how to compute this number?
Im confused
ok lets go slow do you know what \(8!\) means ?
ya 8*7*6*5*4*3*2*1
if you have 8 different letters, or symbols or whatever, the number of ways they can be arranges is \(8!\) so you got that part yes?
ok good, but in this case you have some letters that you cannot tell apart
Okay im not sure how to do this srry
there are two "E" and the number of ways to order the 2 "E" is 2
and also there are 3 "L" and the number of ways to order the 3 "L" are \(3!=3\times 2=6\)
okay
so to answer your question, you have to divide \[\frac{8!}{2!3!}=\frac{8\times 7\times 6\times 5\times 4\times 3\times 2}{2\times 3\times 2}\]
cancel first, multiply last
you can compute \[8\times 7\times 6\times 5\times 2\] for example
Okay so it will be 6720
still probably need a calculator i get \(3360\) http://www.wolframalpha.com/input/?i=8*7*6*5*2
or just type it in directly and don't bother with the cancellation still 3360 http://www.wolframalpha.com/input/?i=8!%2F%282!3!%29
O okay
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