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a water tunnel has a circular cross section where the diameter diminishes from 3.6 to 1.2 if the velocity of water is 3.0 m/s in the larger part of the tunnel what is the velocity of water in the smaller part of the tunnel
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Bernoulli's equation will give you the answer.
27m/s ? I believe this is it
Hmmm, I'm not sure what level of physics you are at, but I would say 12 m/s
AS the flow rate remain constant so the answer is 27 m/sec
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Using the equation of continuity of flow, \(A_1V_1=A_2V_2\) \(\pi (r_1)^2 V_1=\pi (r_2)^2 V_2\) \((r_1)^2 V_1=(r_2)^2 V_2\) plug it all in, \((3.6)^2 (3)=(1.2)^2 V_2\) \(V_2=27ms^{-1}\)
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