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Can you help me please? Find the area of the region between the curves y=abs(x) and y=(x^2)-2
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Start with the limits of integration for the integral. For the limits of integration, we find where \[\left| x \right|=x^{2}-2\]
I would take advantage of the symmetry with the y axis. Both equations are symmetric with respect to the y axis.
They intersect at x=-2 and x=2, so we do:\[\int\limits_{-2}^{2}(\left| x \right|-(x ^{2}-2))dx\] abs(x) is first because abs(x)>x^2-2
on that interval
And yeah we could do it from 0 to 2 and multiply that by 2
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okay, so I integrated from 0 to 2 and then multiplied by 2 to find the area on the other side. My final answer was 20/3 and it was correct. Thank you both so much!
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