how to find inverse function?

Question

aravindg · Answer

f(x)=|x+2| +2021

hartnn · Answer

you can try using
$|x|=\sqrt{x^2}$

terenzreignz · Answer

I thought you were repeating @arpan2021 's stunt @AravindG 
o.O
:)

aravindg · Answer

lol

hartnn · Answer

me too! ^

aravindg · Answer

thanks @hartnn  for ur help anyway :)

terenzreignz · Answer

But you guys know that absolute values are not bijective... so the inverse may not be a function on its entire range...

aravindg · Answer

good point @terenzreignz

hartnn · Answer

y= |x+2|+2021
x = |y+2| +2021
x-2021 = |y+2|
$\pm$(x-2021) = y+2
inverse is  $\pm$(x-2021)-2

hartnn · Answer

or do that^

aravindg · Answer

But for a function to have inverse shouldnt it be bijective?

terenzreignz · Answer

Well, @AravindG didn't say inverse *function* after all...

aravindg · Answer

@terenzreignz  really^^

terenzreignz · Answer

cr*p

terenzreignz · Answer

I am ashamed T.T

agent0smith · Answer

You can limit the domain of the function to x>-2 or x<-2 and then it's an easy inverse to find :P

aravindg · Answer

So now what will be the answer?no inverse function?

aravindg · Answer

yep I bet we need to do what @agent0smith  says :)

agent0smith · Answer

Well technically that's correct, there's no inverse function. 

Functions that aren't one to one dont have inverses - if it fails the horizontal line test, it fails to get an inverse.

terenzreignz · Answer

Well, split the domain at the vertex of the darned absolute value...

aravindg · Answer

yep lets get back to help arpan ..He is back with new stunts lol

agent0smith · Answer

But if the question doesn't specify restrictions, then it has no inverse.

hartnn · Answer

lol, enough @AravindG made up this question :P
2021 comes from arpan 2021...

agent0smith · Answer

Oh yes, i assumed it was not a real question... then he seemed to turn it into one :P

aravindg · Answer

yeh after all learning is enjoying :)