Question

What are the coordinates of the x-intercepts of the graph of y = 2x2 + 6x – 20? (1 point)

Answer 1

Y = 2x2 + 6x-20.

So are you aware of what is an x-intercept?

Answer 2

Yes

Answer 3

ok. basically x-intercept is a point where the parabola hits x-axis i.e. a spot where y equals 0.

So y = 0

Hence 0 = 2x2+6x - 20.

divide both sides by 2 -

0 = x2+3x-10

= x2+5x-2x-10 = 0.

Solve for x, (x,0) is the x-intercept.

Answer 4

These are the choices:
A. (–5, 0), (2, 0)
B. (5, 0), (–2, 0)
C. (–4, 0), (10, 0)
D. (4, 0), (–10, 0)

Answer 5

Ok

Answer 6

so @TrustMeAndWeWillGoFar why dnt u find it out?

Answer 7

I will, I am working on it.

Answer 8

So far I have \[20=2x2+6x\]

Answer 9

Now what?

Answer 10

well @TrustMeAndWeWillGoFar i've made that much simpler already.

20 = 2x2+ 6x

divide by 2 on both sides -

10 = x2+3x

x2+3x-10 = 0

x2+5x-2x-10 = 0 (splitting middle term.)

now if u can solve

Answer 11

hi i need help with Quadrilaterals

Answer 12

@fun if u can write ur qn separately

Answer 13

\[x2+5x=2x\]

Answer 14

What about that?

Answer 15

Then subtract 5x.

Answer 16

\[2x=-3x\]

Answer 17

x2+5x-2x-10 = 0

u can factorise it.

x(x+5) -2(x+5) = 0

(x-2)(x+5) = 0 (taking x+5 common)

so either x-2 = or x+5 = 0

x = 2, or x = -5

Answer 18

Ok so it would be \[(2,0) and (-5,0)\]

Answer 19

yes.

Answer 20

Cool thanks. I'm going to close the question nowe.

Answer 21

now*