Question

Solve for x in the proportion 2x/16+30=-1/x
x = 8 and x = −8
x = 8 and x = −15
x = −8
x = −3 and x = −5

Answer 1

@jim_thompson5910

Answer 2

is there an x in the denominator on the left side?

Answer 3

yea 16 @jim_thompson5910

Answer 4

so is the equation

\[\large \frac{2x}{16x+30} = -\frac{1}{x}\]

Answer 5

the 1 is negitive not the whole thing but the rest is right @jim_thompson5910

Answer 6

ok so

\[\large \frac{2x}{16x+30} = \frac{-1}{x}\]

Answer 7

right?

Answer 8

yea @jim_thompson5910

Answer 9

\[\large \frac{2x}{16x+30} = \frac{-1}{x}\]


\[\large 2x*x = -1(16x+30)\]


\[\large 2x^2 = -16x-30\]


\[\large 2x^2+16x+30 = 0\]


\[\large 2(x^2+8x+15) = 0\]


\[\large x^2+8x+15 = \frac{0}{2}\]


\[\large x^2+8x+15 = 0\]


\[\large (x+3)(x+5) = 0\]


I'll let you finish.

Answer 10

x = −3 and x = −5? is that right @jim_thompson5910

Answer 11

yep, you got it