Use matrices to solve ths system.

https://www.connexus.com/content/media/642756-1302012-33559-PM-1512522299.png

Question

Use matrices to solve ths system.

https://www.connexus.com/content/media/642756-1302012-33559-PM-1512522299.png

anonymous · Answer

cannot see anything from the link!

anonymous · Answer

Top line: 2x+3y=4
Bottom line: 5+8y=11

anonymous · Answer

so, you have matrix $$\left[\begin{matrix}2 & 3&4 \ 5 & 8&11\end{matrix}\right]$$

anonymous · Answer

That's where i get stuck

anonymous · Answer

do you know how to take rref form?

anonymous · Answer

row1 /2 you get              1     3/2    2
 you have a new matrix  5       8      11

anonymous · Answer

from the new one,  (-5)*row 1 + row 2 ---> row 2 you get 
       a new matrix.      1   3/2    2
                                      0    1/2  1

anonymous · Answer

now, (-3) row 2 + row 1---> row1
2* row 2 ----> row 2 
you have a very new matrix 1   0    -1
                                                   0   1     2
 it means, x = -1
                   y = 2

anonymous · Answer

Is that the final answer?

anonymous · Answer

that 's the process to get rref form. and you should know how to do that. This is the very basic step. if you take linear  algebra , no way to step up if you don't know how to get rref by hand
Yes, that's is final answer