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Mathematics 6 Online
OpenStudy (anonymous):

Need help with Graphing Square Root Functions.

OpenStudy (anonymous):

Don't really understand how to do this lol

OpenStudy (jdoe0001):

what's a DOMAIN?

OpenStudy (anonymous):

Set of values

OpenStudy (jdoe0001):

what's a RANGE?

OpenStudy (anonymous):

Set of all possible output values. Domain is usually for x and Range is usually for y

OpenStudy (jdoe0001):

so, would it be fair to say in => y=2x, if x={1,2,3} <- is the DOMAIN and y would be {2,4,6} respectively <- is the RANGE?

OpenStudy (anonymous):

Yeah. 2 x 1 = 2, 2x2 = 4, 2x3 = 6

OpenStudy (jdoe0001):

though rereading your question and looking at the picture you have there, I see nothing in there saying anything about graphing them :)

OpenStudy (phi):

to do these problems, you should remember this DO NOT TAKE ROOTS OF NEGATIVE NUMBERS. that means in the first problem 3x+4 ≥ 0 solve for x to find what x values (what domain) is allowed.

OpenStudy (jdoe0001):

in the case of \( y=2\boldsymbol{\sqrt{3x+4}}-5 \), as @phi already pointed out, the only thing you'd need to keep an eye, is that the root doesn't turn negative, otherwise is an "imaginary" value

OpenStudy (jdoe0001):

so you'd need to bear in mind --> What values can X take, that will not turn the root to a negative number? <-- if the root turns "0", that's ok, because \(\sqrt{0}=0\)

OpenStudy (jdoe0001):

so, that's more or less what they're asking

OpenStudy (jdoe0001):

the 2nd question trhere is more or less the same matter

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