Question

Calculate the total heat (in J) needed to convert 22.00 g of ice at -6.00 degrees C to liquid water at .5 degrees C

Answer 1

q=mcΔT where
q=heat energy
m=mass
c=specific heat
ΔT=change in temperature=Tf-Ti

Answer 2

copy paste from yahho, much better, now...

Answer 3

q=22.00gX-6.00 (I might be wrong at this part, I might of actually had to put the amount of temperature that you WANT it to be not what it already is)X.5+-6.00

Answer 4

-122,X-5.95

Answer 5

725.9 Joules

Answer 6

This looks right to me!

Answer 7

well uh @Hyperchemist, at 0 C there is something called sp. latent heat of fusion to convert ice to water which i think u have not considered.

which if considered to be 336 J/g would be 336x22 = 7392 J.