Calculate the total heat (in J) needed to convert 22.00 g of ice at -6.00 degrees C to liquid water at .5 degrees C

Question

anonymous · Answer

q=mcΔT where
q=heat energy
m=mass
c=specific heat
ΔT=change in temperature=Tf-Ti

anonymous · Answer

copy paste from yahho, much better, now...

anonymous · Answer

q=22.00gX-6.00 (I might be wrong at this part, I might of actually had to put the amount of temperature that you WANT it to be not what it already is)X.5+-6.00

anonymous · Answer

-122,X-5.95

anonymous · Answer

725.9  Joules

anonymous · Answer

This looks right to me!

anonymous · Answer

well uh @Hyperchemist, at 0 C there is something called sp. latent heat of fusion to convert ice to water which i think u have not considered. 

which if considered to be 336 J/g would be 336x22 = 7392 J.