Question

HELP! PLEASE

Answer 1

\[-6\sqrt{15s ^{3}}\times2\sqrt{75}\]

Answer 2

so is this true that -6 x 2 = -12, and \[\sqrt{15s^3} . \sqrt{75} => \sqrt{15s^3 . 15 . 5 }\]

Answer 3

So from here how I can simplify ?

Answer 4

Yes actually you can. since sqrt of 15x15 = 15 itself, we would get,

\[-12 . 15 \sqrt{5s^3}\]

Answer 5

which is -180 sqrt 5s^3.

Answer 6

ohhh okay I get it now thank you

Answer 7

okk can u help me on another one please?

Answer 8

yeah ask

Answer 9

\[10\sqrt{12x ^{3}}\times 2\sqrt{16x ^{3}}\]

Answer 10

Ok. 10x2 = 20,

and \[\sqrt{x^3} . \sqrt{x^3} = \sqrt{(x^3)^2} => x^3.\]

Answer 11

also \[\sqrt{12} . \sqrt{16} = \sqrt{12 x 4 x 4 } => 4\sqrt{12}\]

Answer 12

Hence,

ans = \[20x^3. 4 \sqrt{12} => 80x^3\sqrt{12}\]

Answer 13

and if u want it further simplified -

\[\sqrt{12} = \sqrt{4x3} => 2\sqrt{3}\]

Answer 14

ok I get lost on this every time why the equation become \[4\sqrt{12}\]

Answer 15

Ok. @safari321

Is it true that -

\[\sqrt{12} . \sqrt{16} = \sqrt{12 } . \sqrt{4x4} ?\]

Answer 16

yes

Answer 17

\[\sqrt{4x4 } = 4 ?\]

Answer 18

doesn't it equal 16?

Answer 19

and what is \[\sqrt{16} = ?\]

Answer 20

16 is a perfect square so it would have a whole number square root, right?

Answer 21

oh yeah the square root sorry

Answer 22

Hence \[\sqrt{12} . \sqrt{16} => \sqrt{12} . 4 => 4\sqrt{12} .\]

Answer 23

yes I now get that part

Answer 24

Yes.

actually \[80x^3\sqrt{12}\]

Answer 25

can be further simplified.

\[\sqrt{12} => \sqrt{4.3} => 2.\sqrt{3}\]

Answer 26

So best simplified answer -

\[80x^3.2\sqrt{3} => 160x^3\sqrt{3}\]

Answer 27

ohhhh ok than you so much @luckythebest

Answer 28

yes np :)

Answer 29

:) I just might pass my test thanks to you

Answer 30

lol i would say prep hard, do your best and have confidence in yourself. you would do much better than passing then :)

Answer 31

:) ok thanks again