Use the computational properties of logarithms to write the expression ln (x – 1)(x + 6) in another form.
Know the rules of logs for things that are added and subtracted?
No
\[log(m\cdot n) = log(m)+log(n)\]That one applies here, if that log is around both of the terms.
The other two are: \[log\left(\frac{m}{n}\right) = log(m)-log(n) \\ log(m^n)=n\cdot log(m)\]
log(x-1)+log(x+6)?
So if your is \(ln[(x-1)(x+6)]\) then yah, \(ln(x-1)+ln(x+6)\)
and that's it?
Not much you can do to what is inside the braces unless you could bring things to a power and then have the stuff simplify. Then your right had side would be e to the something and it should be solvable... but other than that, there is nothing else that could be done.
This is the type of case where you could do more. \[ln x = 5\implies e^{ln x}=e^5 \implies x=e^5\] If they do not give you a right hand side, there is nothing else to be done.
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