Question

The DIAMETER of a sphere is doubled. What is the new volume of the sphere?

Answer 1

Sphere Volume = 4/3 • π • r³ = ( π •d³)/6

Answer 2

Radius is half the diameter, so if the diameter doubles, the radius doubles.

If the initial radius is r, then the volume is:
\[\Large V _{initial}= \frac{ 4 }{ 3 } \pi r ^3\]
The new radius is 2r, so final volume is:
\[\Large V _{final}= \frac{ 4 }{ 3 } \pi (2r) ^3\]