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Physics 12 Online
OpenStudy (anonymous):

Electricity question

OpenStudy (anonymous):

OpenStudy (anonymous):

i used the formula t = Q/I t = 3.204 x 10^-19 / .1 t = 3.204 x 10^-18 which is the time for 1 electron, therefore 3.204 x 10^-18s = 1e 1s = 3.121 x 10^17 correct??

OpenStudy (anonymous):

so like 3 x 10^17 electrons per second?

OpenStudy (anonymous):

current= Q/t current=0.1A, t=1s Q=0.1C where \(1e=1.6x 10^{-19} C\) so, no.of electrons =\(\frac{0.1}{1.6x 10^{-19}}\)

OpenStudy (unklerhaukus):

\[I=0.10[\text A]\\=0.10\tfrac{[\text C]}{[\text s]}\\=0.10\tfrac{[\text C]}{[\text s]}\div1\\=0.10\frac{[\text C]}{[\text s]}\div\frac{1.6\times10^{-19}[\text C]}{[\text {electron}]}\\=0.10\div1.6\times10^{-19}\frac{[\text {electron}]}{[\text s]}\\=6.24\times10^{17}\frac{[\text {electron}]}{[\text s]}\]

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