Question

Could someone please help me/teach me to graph vector <5i + 4j -3k>.

Answer 1

5i + 4j -3k is the same as <5, 4, -3>

Answer 2

Yes, i see that part. It's graphing it that tricks me.

Answer 3

create an xyz axis

start at the origin (0,0,0)

then you move 5 units along the x axis (in the positive x direction)
move 4 units along the y axis (in the positive y direction)
then 3 units along the z axis (in the negative z direction)

where you end up is where the tip of the vector will lie
the initial point of the vector will be at (0,0,0)

Answer 4

z is the part that i cannot graph.

Answer 5

it's hard to draw out or visualize, but give it your best shot

ideally, you would use interactive software to graph (so you can spin the axis around)

Answer 6

imagine the xy axis is the floor

Answer 7

you would go to the point (5, 4) on the floor

then you would sink 3 units into the floor to land at (5, 4, -3)

Answer 8

Hmm. I can't really imagine this. So because z is negative it would go downward?

Answer 9

correct

Answer 10

brb