Mathematics
8 Online
OpenStudy (anonymous):
Solve each system of equations by graphing.
y = 2x + 1
y = -x + 1
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OpenStudy (anonymous):
y = 2x + 1
y = -x + 1
---------------------
2x + 1 = -x + 1
solve for x
OpenStudy (anonymous):
I don't really know how to do that.
OpenStudy (anonymous):
Could you help me? I'm sorry :(
OpenStudy (anonymous):
|dw:1367376587762:dw|
OpenStudy (anonymous):
How did you do that all? I don't get it :(
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OpenStudy (anonymous):
And how do I graph it?
OpenStudy (anonymous):
@some_someone
OpenStudy (anonymous):
Graph: y = 2x + 1
&
Graph: y = -x + 1
OpenStudy (anonymous):
graph the two lines on a graph and then look for the point of intersection
OpenStudy (anonymous):
I don't get how you graph them?! :(
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OpenStudy (anonymous):
You have to talk me through this, we learned it today and I was too scared to ask for help
OpenStudy (anonymous):
the line equation is in the form y=mx+b where m is the slope of the line, and b is the y-intercept
OpenStudy (anonymous):
Yes I get that part
OpenStudy (anonymous):
so for y = 2x + 1 identify the slope and the y-intercept
OpenStudy (anonymous):
remember:
y = mx + b
--where: m is the slope; & b is the y-intercept
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OpenStudy (anonymous):
I did what the someone guy said and it was (0,1) but I think I need another one
OpenStudy (anonymous):
?
OpenStudy (anonymous):
graph y = 2x + 1
OpenStudy (anonymous):
How do you graph that?
OpenStudy (anonymous):
Could you do the graph for me as an example? I'm lost
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OpenStudy (anonymous):
slope = rise / run = 2/1
b or y-intercept = 1
OpenStudy (anonymous):
What do I do with the (0,1) ?
OpenStudy (anonymous):
thats the answer but the question asking you get that by graphin
OpenStudy (anonymous):
Ohhhhh
OpenStudy (anonymous):
yeah (0,1) is the solution.
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OpenStudy (anonymous):
Wait so I go up 2 and then to the right 1?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
what about the other 1
OpenStudy (anonymous):
slope is -1 so you go down 1 and right 1
OpenStudy (anonymous):
I have to have 2 lines though
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OpenStudy (anonymous):
everything clear now?
OpenStudy (anonymous):
I thoguht I was suppose to go up 2. On yours it says the point of intersection is 1
OpenStudy (anonymous):
ya thats where the two lines intersect
OpenStudy (anonymous):
OpenStudy (anonymous):
could you use this and do it on here
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OpenStudy (anonymous):
@dav21
OpenStudy (anonymous):
ok first im gonig to draw y = 2x + 1
OpenStudy (anonymous):
OpenStudy (anonymous):
first plot the y-intercept which is at point (0,1) then go up 2 and right 1 cause thats the slope
OpenStudy (anonymous):
ok got that part
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OpenStudy (anonymous):
ok connect all the dots and make a straight line
OpenStudy (anonymous):
ok got that part too. But I have to have another line and stuff. There has to be 2.
OpenStudy (anonymous):
ya now graph y = -x + 1
OpenStudy (anonymous):
I don't understand how you graph these unless you give me the points and tell me which way to go
OpenStudy (anonymous):
y = -x + 1, first plot the y-intercept
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OpenStudy (anonymous):
the y-intercept is at 1
OpenStudy (anonymous):
same as the first line
OpenStudy (anonymous):
how many do I go to the right and up
OpenStudy (anonymous):
y = (-1)x + 1, because our slope is negative we go down 1 and right 1
OpenStudy (anonymous):
positive slope means go up and right, negative slope means go down and right
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OpenStudy (anonymous):
Thanks! Can you help me with a few moer?
OpenStudy (anonymous):
@dav21
OpenStudy (anonymous):
x + y = 4
x + y = 2
OpenStudy (anonymous):
ok first lets get the two equations in y = mx + b form
OpenStudy (anonymous):
ok.
I need help with that
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OpenStudy (anonymous):
x + y = 4, bring the x on the right side
OpenStudy (anonymous):
ok now what
OpenStudy (anonymous):
do the same for the other line as well
OpenStudy (anonymous):
show me what you have so far
OpenStudy (anonymous):
I have x + y = 4
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OpenStudy (anonymous):
x + y = 2
OpenStudy (anonymous):
x + y = 4, if we subtract x from both sides of the equation what do we have
OpenStudy (anonymous):
y = 4x?
OpenStudy (anonymous):
|dw:1367379514405:dw|