Question

help

Answer 1

with?

Answer 2

Question?

Answer 3

Hey didn't I just do this?

Answer 4

No different one.

Answer 5

when doing partials, treat extra variables like constants

Answer 6

Fx is the partial derivative of the function with respect to x and Fy is the partial derivative of the function with respect to y. Once you take these partial derivatives, plug in the coordinates and you will have the solutions

Answer 7

\[\frac{\partial \text{}}{\partial x}\left(x^4+5 x^2 y\right)=4 x^3+10 x y\]
Then use (1,2) and find the values,
Try that and the other partial derivative

Answer 8

Use dumbcow's idea as well :)

Answer 9

whats dumbcows?

Answer 10

treating the extra variables as constants..

Answer 11

Fx(1,2) = 4(1^3)+10*(1)*(2)..

Answer 12

5 and y, in 5x^2y will be constants, so when you derive, you will get 10xy

Answer 13

\[\alpha/\alpha y = 4x+10y?\]

Answer 14

no no no.. when you're differentiating with respect to y, treat x as a constant. The 4x^3 would then go to zero, and the 10x^2 will just remain the same as the 'y' variable drops off.

Fy = 5x^2

Answer 15

In \[\frac{\partial \text{}}{\partial y}\left(x^4+5 x^2 y\right)\]
Treating \(x^4\) as constant, and \(5x^2\),
You get
\(5x^2\)

Answer 16

Ohhh. so constant is always zero.

Answer 17

@.Sam.

Answer 18

Yes

Answer 19

Because we are talking the partial derivative of y, x^4 will be a constant, just like a number 5,10,12. So derivative will give zero

Answer 20

Ok thank you

Answer 21

Welcome :)