Question

i give medals and fans

Answer 1

Solve\[2x ^{2}=14x+20\]

Answer 2

Put all terms in one side
\[2x^2-14x-20=0\]

Answer 3

You can use either completing the square or quadratic equation here

Answer 4

so it would be
\[\frac{ -14x \sqrt{14x ^{2}-2x ^{2}*20} }{ 2*2x ^{2} }\]

Answer 5

\[2x^2-14x-20=0 \\ \\ Ax^2+Bx+C=0 \\ \\ x=\frac{-B \pm \sqrt{B^2-4AC}}{2A}\]

Answer 6

\[x=\frac{-(-14)\pm \sqrt{(-14)^2-4(2)(-20)}}{2(2)}\]

Answer 7

Did you get it?

Answer 8

\[\frac{ 14\sqrt{356} }{ 4}\]

Answer 9

\[\frac{14\pm\sqrt{356}}{4}\]


now 356 is divisible by four

both the solutions wil have a square root in them

Answer 10

\[28\sqrt{89}\]

Answer 11

i got \[\frac{ 7\sqrt{89} }{ 2 }\]

Answer 12

From Unkle's view,
\[x=\frac{14\pm\sqrt{356}}{4} \\ \\ x=\frac{14}{4}\pm \frac{\sqrt{356}}{4} \\ \\ x=\frac{7}{2}\pm \frac{2\sqrt{89}}{2} \\ \\ x=\frac{7}{2} \pm \sqrt{89}\]
Split it up, since we have plus and minus
\[x=\frac{7}{2}+\sqrt{89} ~~~~OR~~~~ x=\frac{7}{2}-\sqrt{89}\]

Answer 13

ok thnx

Answer 14

*\[ x=\frac{14}{4}\pm \frac{\sqrt{356}}{4} \\ \\ x=\frac{7}{2}\pm \frac{2\sqrt{89}}{4} \\ \\ x=\frac{7}{2} \pm \frac{\sqrt{89}}2\]

Answer 15

ffff, nowonder it feels weird

Answer 16

You get
\[x=\frac{7}{2}+\frac{\sqrt{89}}{2} ~~~~OR~~~~ x=\frac{7}{2}-\frac{\sqrt{89}}{2}\]