Question

i give medals and fans

Answer 1

solve
\[2x ^{2}-8x=-7\]

Answer 2

Apply http://openstudy.com/users/.sam.#/updates/5181023ce4b0aaab28b79617

Answer 3

add 7 to both sides.
\(2x^2 - 8x +7=0\)
then apply the general formula.

Answer 4

\[\frac{ -(-8)\sqrt{8x ^{2}-2x*7} }{ 2*2 }\]

Answer 5

it's \(x=\frac{-(-8)\pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}\) though

Answer 6

ok so simplify all that its \[\frac{ 8\sqrt{64-14} }{ 4 }\]

Answer 7

u forgot to multiply the 14 by 4? the others are right

Answer 8

so \[\frac{ 8\sqrt{64-56} }{ 4 }\]

Answer 9

yup! you've got it. :)

Answer 10

Its soo easy :D

Answer 11

loool

Answer 12

so simplify that its \[\frac{ 2\sqrt{2} }{ 2 }\]

Answer 13

wait. you've missed the plus minus out.
\(\frac{8 \pm \sqrt{8}}{4}\)=\(\frac{8 \pm 2\sqrt{2}}{4}=\frac{4 \pm \sqrt{2}}{2}\)

Answer 14

ok thnx

Answer 15

you’re welcome :)