Question

f(n)= 7/n^2-7n+10

a) asymptotes: n=2, hole: n=5
b) asymptotes: n=5, n=-2, no hole
c) asymptotes: n=5, hole: n=2
d) asymptotes: n=5, n=2, no hole

Answer 1

I don't think there is an asymptote for this function. :)

Answer 2

@Linyu Yes, they are

Answer 3

Ops vert sorry, I missed 7 over n to the power of 2.

Answer 4

so?

Answer 5

What is hole?

Answer 6

no hole

Answer 7

you should calculate\[\lim_{n \rightarrow 5}(\frac{ 7 }{ n ^{2} }-7n+10)\]
\[\lim_{n \rightarrow 2}(\frac{ 7 }{ n ^{2} }-7n+10)\]

Answer 8

sorry, not undefined, not continuous

Answer 9

Still kinda confused but i think i understand. im gonna say "B" and hope for the best. thank you.

Answer 10

Sorry it's incorrect :-(
Look, do it like ... First factorise the denominator and see what happens...

Answer 11

n=a is vertical asymptote only if
\[\lim_{n \rightarrow a}f(x)=\]

Answer 12

infinity

Answer 13

^ my response is to @Jossi_baby101 ...

Answer 14

thank you.

Answer 15

Is it clear??? If yes, then pleasure ... If no, you can ask any doubts you have since it is OPENstudy :-)

Answer 16

im kind just playing it error and trial. i dont have a teacher bc its online so i just have to hope for the best. i dont understand the equations or the way you figure out anything.

Answer 17

See it is like...


Let's try and hope for the best... don't worry :-)