Question

Solve the equation for solutions in the interval [0, 2pi)
sin 2x + sin x = 0

Answer 1

http://answers.yahoo.com/question/index?qid=20080727210835AAUO01T

Answer 2

That is minus @FaceYourFears

Answer 3

^~^ I just gave him a link lol

Answer 4

I am starting over from @lacypennelll

Answer 5

Right, so @beverly42 are you there?

Answer 6

2sinxcosx+sinx=0
sinx(2cosx+1)=0

Answer 7

For Solving this Question, I would like to ask you that, do you have the detailed conception of : SetTheory, and Theory of Limiting Numbers

Answer 8

sinx=0, x=k(pi) , where k=0,1,2,........
due to interval [0,2pi) k=0,1 so x=0,pi
2cosx+1=0
2cosx=-1
cosx=-1/2, x=5(pi)/6+2k(pi), x=11(pi)/6+2k(pi)
due to interval [0,2pi) k=0 so x=5(pi)/6, 11(pi)/6