a charge of 1uc is given to one plate of a parallel plate capacitor 0.1uF and a charge of 2uc given to the other plate .find the potential difference develop b/w the plate.

Question

anonymous · Answer

@UnkleRhaukus

unklerhaukus · Answer

$$C[\text F]=\frac{\Delta Q[\text C]}{\Delta V[\text V]}$$

anonymous · Answer

nt getting

unklerhaukus · Answer

$$\Delta V=\frac{\Delta Qd}{\varepsilon A}$$

ganeshie8 · Answer

Qeffective = 2-1 = 1uc
so just for visualizing, if u short the capacitor, .5 uC charge would move from second plate to first plate.

so Q on plate we can assume as .5 uC
we can use Q=CV now
.5 uC = .1uF * V

V = .5/.1 = 5V