Let U be the subspace of R^3 spanned by [1,-1,1]. Find a basis for the orthogonal complement of U.
The collection of all vectors in R^3 that are orthogonal to every vector in U is called the orthogonal complement of U.
you are essentially given a line, and asked to define the plane
Oh, okay.
more like a normal vector
So my line is {1,-1,1}
find the null space
but how can i find the nullspace if i don't have a matrix?
with the plane equation, you can then determine 2 vectors to form a basis from
or, just trial and error some dot products to fit
[1,-1,1] is a matrix
trial and error is prob the easiest way to do this one...you can do it in your head
oh okay so [1,-1,1][x1,x2,x3] = [0,0,0]
oh so wait do i have to find an orthogonal component first? and then find the basis of that?
does the basis have to be orthogonal as well, and unitized?
im just finding a basis for the orthogonal complement to U
x-y+z = 0 [1,1,0] [0,1,1] would work for a trial and error
Then the orthogonal complement of W in V is the set of vectors u such that u is orthogonal to all vectors in W ( http://ltcconline.net/greenl/courses/203/Vectors/orthogonalComplements.htm) seems like just 2 non-parallel vectors is all thats needed
oh okay so whichever one of those is a linear combination of [1,-1,1] is a basis for U orthogonal complement
i was getting the orthonormal basis mixed in my head :) an "orthonormal" basis is a basis where all the vectors in it are perpendicular as well. and have unit length.
oh okay yeah this is orthogonal haha
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