Question

3/m-4+1/3(m-4)=6/m Help! Solving rational expressions

Answer 1

\[\frac{ 3 }{ m }-4+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{ m }\]is it like this?

Answer 2

yes! @Linyu I just need to know how to do it, my book doesn't give an example for ones like this

Answer 3

you need to convert the denominators to the same form\[\frac{ a }{ b }+\frac{ c }{ d }=\frac{ ad }{ bd }+\frac{ cb }{ bd }\]

Answer 4

@ohhailayne are you with me?

Answer 5

7/m-4? @Linyu

Answer 6

hmm... not sure if you catch up.
Okay I'll try to solve this one step by step so you could understand

Answer 7

10/m-4

Answer 8

I think I've got it? @Linyu

Answer 9

\[\frac{ 3 }{ m }-\frac{ 4 }{ 1 }+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{ m }\]
convert the denominator into 3m(m-4) we have\[\frac{ 3(m-4) }{ 3(m-4) }\times \frac{ 3 }{ m }-\frac{ 3m(m-4) }{ 3m(m-4) }\times \frac{ 4 }{ 1 }+\frac{ m }{ m }\frac{ 1 }{ 3(m-4) }=\frac{ 3(m-4) }{ 3(m-4) }\times \frac{ 6 }{ m }\]

Answer 10

now all the denominators are the same 3m(m-4) so feel free to cancel them out. And you'll get\[3(m-4)\times3-3m(m-4)\times4+m=3(m-4)\times6\]

Answer 11

the problem should be \[\frac{ 3 }{ m-4 }+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{m? }\]

Answer 12

Oh! that will be better to solve

Answer 13

yes! so I think the answer is 10/m-4 @Linyu

Answer 14

3m(3)+m=3(m-4)(6)
9m+m=18m-72
10m=18m-72
0=8m-72
72=8m
m=72/8
m=9

Answer 15

the method is the same

Answer 16

thanks @Linyu

Answer 17

I hope you understand. Not only know the answer.