Given the vectors u=(-2,3) and v=(2,1), determine a vector w as 2(u-w)+4(v+w)=0
yeah
are you sure you copy the right problem? just make sure about what we should do
@Teuzer knock, knock
ok
let w (x,y ) so tell me what u-w =??
in this problem 0= zero vector
let it aside, not touch it yet
just answer me, u-w =...
don't know
my god, u -w = (-2 -x, 3 -y) . you really not know about that? are you kidding me?
ohh. I know this. but how can I discovery w ?
take steps, please.!! ok, so how about 2 (u - w) =?
I believe the final result is w=(2,5)
Is that right?
how do you get it? teach me back, please
@phi rescue, please
wel. 2(-2-x,3-y) + 4(2+y,1+y) (-4-2x,6-2y)+(8+4y,4+4y) (4+2x,10+2y) x=4/2 and y= 10/2
the last part is wrong, it is 4 ( 2 +x , 1 +y ) not 4 (2 +y ,....) that's mistake,
you redo, that's the right set up , just fix that mistake . show me your work
ok
I just wrote it wrong. but the result is right
nope, re calculate
so wherer it's wrong? i don't see it.
first term for x: -4 -2x +8 +4x = 4 +2x = 0 ---> 2x = -4---> x =-2
see it?
Ohh yeah. just the signal.
thnks phi for reply my tag. :)
value of y is the same. @Teuzer it not "just the signal" in linear, it's wrong.
I got, i meant my mistake was upon the signal.
***Given the vectors u=(-2,3) and v=(2,1), determine a vector w as 2(u-w)+4(v+w)=0 I would divide both sides by 2 to simplify 2(u-w)+4(v+w)=0 u - w + 2(v+w)=0 distribute the 2 to get u - w +2v + 2w= 0 combine 2w-w to get w: u + 2v + w = 0 add -u -2v to both sides w = -u -2v notice this is like ordinary algebra. now replace u and v with their vector values. combine like components.
hehehee.... that's why I tag him, thanks phi . Perfect performance.
You still have to find the vector w.
Good thinking.
@phi, the leftover is the Asker's responsibility. easiest way, i gave out, professional way, you gave out. that's it.
to finish this, what is -u if u is (-2,3) ? what is -2v if v is (2,1) ? once you get those vectors add corresponding components.
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