Question

One simple question:

y =1/4 cos ((2pi)/3) theta

How do I find the period and amplitude of this equation?

Answer 1

Well this seems to just confuse me more... how would you determine the amplitude and period from this circle?

Answer 2

Is your question correct

Answer 3

\[y=\frac{1}{4}\cos \left(\frac{2\pi }{3}\right)\]?

Answer 4

Yes, that is my question.

Answer 5

I think you missed an x or something

Answer 6

\[y=\frac{1}{4}\cos \left(\frac{2\pi }{3}-\theta\right) \]?

Answer 7

No, that is exactly as it appears, although the subtract sign before the theta was not there.

Answer 8

You get a straight line for that

Answer 9

Hmm, that's what I got at first as well. That is why I came here for help.

Answer 10

I'm sure there is a variable inside it, I think its
\[y=\frac{1}{4}\cos \left(\frac{2\pi }{3}x\right)\]

Answer 11

We got a nice cosine graph after that

Answer 12

I'm guessing that theta sign, can be a stand-in for a variable, because otherwise this problem doesn't seem to make sense. Thanks for this graph.

Answer 13

Amplitude will be 1/4, and period is
\[T=\frac{2\pi}{B}\]
---------------------
\[B=\frac{2\pi}{3}\]
Then period is
\[T=3\]

Answer 14

Thanks very much for your help!

Answer 15

welcome :)