Chain RULE!!

f(x) = (4x-5)(3x^2-x+2)^2/3

Question

Chain RULE!!

f(x) = (4x-5)(3x^2-x+2)^2/3

zepdrix · Answer

`Chain RULE!!` also the Product RULE!!

:) Need help finding the derivative?

anonymous · Answer

yes i dont know the steps on this one.. i understand the chain rule but this problem just confuses me

zepdrix · Answer

$$\large f(x)=(4x-5)(3x^2-x+2)^{2/3}$$$$\large f'(x)=\color{royalblue}{(4x-5)'}(3x^2-x+2)^{2/3}+(4x-5)\color{royalblue}{\left((3x^2-x+2)^{2/3}\right)'}$$

We start by applying the `Product Rule`.
Understand the setup?
Derivative of the first, times the second, then we add the first times derivative of the second.

The blue terms are the ones we'll need to take the derivatives of.
All we've done so far is set it up.

zepdrix · Answer

What is the derivative of that first blue term? :)
Can you solve that one?

moonlitfate · Answer

What's so confusing about it for you? x: The chain rule used to REALLY confuse me...

moonlitfate · Answer

@j3llimari3 -- are you still there?

anonymous · Answer

im here

anonymous · Answer

derivative of the blue is (4)