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Physics 22 Online
OpenStudy (anonymous):

I am so confused! Please Help! A spring is stretched to a displacement of 30 cm where it experiences a restoring force F. If the spring is then stretched to a displacement of 60 cm , what is the restoring force exerted by the spring

OpenStudy (anonymous):

ok, so the recall went like this, hook's law stated the force to be directly proportional to the displacement. if it is not an upper level question then i guess, if not mistakin, the force f would become twice i.e 2f :wikipedia:

OpenStudy (anonymous):

Thank you so much! Where did you get the 2 from though?

OpenStudy (anonymous):

the formula called hooke's first law says that: "F"(being the restoring force) = "-k"(the spring constant) times "x"(the displacement) the negative is only for notations sake. and yes this means they are proportional, by means of the constant so when we double the x we get 2f :wiki.answers.com:

OpenStudy (anonymous):

okay than, you!

OpenStudy (anonymous):

Don't forget to close the question! :)

OpenStudy (goformit100):

For Solving this Question, I would like to ask you that, do you have the detailed conception of : Restoring forces

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